Question

If a=1. explain how to use the completing the square method to solve a quadratic equation In the form of ax2+bx=c, where a and b are the coefficients of x2 and x respectively and c is the constant (numeric term) and a=1. someone help please.

Answer 1

see below

Explanation:

ax^2+bx=c

Let a =1

1x^2+bx=c

We take the b coefficient, divide it by 2 and then square it

(b/2) ^2

Add this to each side

1x^2+bx + (b/2) ^2=c+ (b/2) ^2

Then simplify the left side

The term inside the square term is b/2

(x + b/2) ^2 = c+ (b/2) ^2

Take the square root of each side

sqrt((x + b/2) ^2) =± sqrt(c+ (b/2) ^2)

(x + b/2) =± sqrt(c+ (b/2) ^2)

Subtract b/2 from each side

x + b/2-b/2 = -b/2 ± sqrt(c+ (b/2) ^2)

x = -b/2 ± sqrt(c+ (b/2) ^2)