Question

The slant asymptote of f(x)=x^2-4x+1/2x-3 is y=1/2x-5/4
t or f

Answer 1

Answer: True

Step-by-step explanation: Trust me bro

Answer 2

True

Explanation:

Given that a function is

`f(x)=(x^2-4x+1)/(2x-3)`

We are to find the slant asymptote if any for this function

Since numerator is of degree 2 and denominator 1, let us divide and then check

Doing long division we find

`f(x)=(1)/(2) [x-(5)/(2) ]-(11)/(4(2x-3))`

Thus we find the asymptote y= the quotient obtained i.e

`(1)/(2) [x-(5)/(2) ]\\=(x)/(2) -(5)/(4)`

Hence asymptote is

`y=1/2x-5/4`

Statement given is true.