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what is the probability of drawing two blue cards if the first card is not included in the second draw? simplify your answer completely

what is the probability of drawing two blue cards if the first card is not included-example-1

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Answer:

5/14

Explanation:

The total number of cards is 8

There are 5 blue cards

P(1st card is blue) = blue/total = 5/8

We take away a blue card

The total number of cards is 7

There are 4 blue cards

P(2nd card is blue) = blue/total = 4/7

The probability of blue blue is P(blue blue ) =

P(1st card is blue)*P(2nd card is blue) =

5/8* 4/7

20/56

We can divide the top and bottom by 4

5/14

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