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Write the standard form of a line that passes through (1, 1) and (3, 4)

User Fysx
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1 Answer

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Answer:

3x - 2y = 1

Explanation:

Step 1: Find the slope

slope m = (y2 - y1)(/x2 - x1)

m = (4 - 1)/(3 - 1) = 3/2

Step 1: Use the formula y = mx + b to solve

This is slope-intercept form of a line. We have a slope of 3/2, and a point (x, y), which is (1, 1). Plug those values into the equation above and solve for b (the only variable we are missing

1 = (3/2)(1) + b

1 = 3/2 + b

1 - 3/2 = b

2/2 - 3/2 = b

-1/2 = b

Step 2: Rewrite the formula using the slope and the b value we just calculated

y = (3/2)x - 1/2

Step 3: Standard form of a line is ax + by = c, where a is a positive integer, so we rearrange the equation from step 2 to standard form.

y = (3/2)x - 1/2

-(3/2)x + y = -1/2 (subtract (3/2)x from both sides)

-3x + 2y = -1 (multiply by 2 to get rid of the fraction on x)

3x - 2y = 1 (multiply by -1 so a becomes positive)

User Omalave
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