Question

PLEASE I NEED HELP! THANK YOU.

Type the correct answer in the box.
Consider the table below.

Complete the standard form of the equation that represents the quadratic relationship displayed above, where a, b, and c are rational numbers.

Answer 1

First set up a linear equation and using the x and y values in the table see if it solves.

It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)

Using the quadratic formula y = ax^2 +bx +c

Build a set of 3 equations from the table:

C is the Y intercept ( when X is 0), this is shown in the table as 6

Now we have y = ax^2 + bx + 6

-2.4 =4a-2b +6

1.4 = a-b +6

Rewrite the equations

a=b/2 -2.1

1.4 = b/2-2.1 +6

b = 5

a = 5/2 -2.1 = 0.4

replace the letters to get y = 0.4x^2 + 5x +6