Question

A=(_3 2),b (4 _6),c=(5 _10)​

Answer 1

first we find x of p:


`x = 2 * ( - 3) - (1)/(2) * 4 + (2)/(5) * 5 \\ = - 6 - 2 + 2 = - 6`

then we find y of p:


`y = 2 * 2 - (1)/(2) * ( - 6) - (2)/(5) * ( - 10) \\ = 4 + 3 + 4 = 11`

so


`p = \binom{ - 6}{11}`

and


`|p| = \sqrt{ {( - 6)}^(2) + {11}^(2) } \\ = √(36 + 121) = √(157) = 12.53`