Question

The molar heat of fusion for water is 6. 01 kJ/mol. How much energy must be added to a 75. 0-g block of ice at 0°C to change it to 75. 0 g of liquid water at 0°C? Use q equals n delta H. 1. 44 kJ 10. 2 kJ 12. 5 kJ 25. 0 kJ.

Answer 1

25.0 kJ

Step-by-step explanation:

6.01 kj/mole heat of fusion. Since this has the unit of moles, we need to convert 75.0 grams of water to moles of water:

(75.0 grams)/(18.0 grams/mole) = 4.17 moles H2O.

q = n(6.01 kj/mole)

q = (4.17 moles)(6.01 kj/mole)

q = 25.0 kJ