Question

Could use someone’s help please

Answer 1

A

Explanation:

Since i = 1 to 3, it is probably quicker to evaluate each sum, that is

4 ×
`(1)/(2) ^(0)` + 4 ×
`(1)/(2) ^(1)` + 4 × (
`(1)/(2)`))²

= (4 × 1) + (4 ×
`(1)/(2)`) + (4 ×
`(1)/(4)`)

= 4 + 2 + 1

= 7 → A