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Could use someone’s help please
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2 votes
Could use someone’s help please

Could use someone’s help please-example-1
User Bhanu Krishnan
by
4.8k points

1 Answer

4 votes

Answer:

A

Explanation:

Since i = 1 to 3, it is probably quicker to evaluate each sum, that is

4 ×
(1)/(2) ^(0) + 4 ×
(1)/(2) ^(1) + 4 × (
(1)/(2)))²

= (4 × 1) + (4 ×
(1)/(2)) + (4 ×
(1)/(4))

= 4 + 2 + 1

= 7 → A

User Ac
by
5.7k points
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