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M∠CBD=4x+52∘

m∠ABC=8x−10∘\qquad m \angle ABC = 8x - 10^\circm∠ABC=8x−10∘


Find m∠CBDm\angle CBDm∠CBD:

User Friedel
by
5.8k points

2 Answers

2 votes

Answer:

68

Explanation:

Khan academy

User KetimaBU
by
6.5k points
1 vote

Answer: The value of ∠CBD is 98°.

Explanation:

Since we have given that

m∠CBD=4x+52∘

and

m∠ABC=8x−10∘

As we know that they are linear pairs.

As we know that a linear pair is a pair of adjacent angles when two lines get intersected by a line say BC.

So, Sum of linear pair is supplementary.


\angle CBD+\angle ABC=180^\circ\\\\4x+52+8x-10=180^\circ\\\\12x+42=180^\circ\\\\12x=180^\circ-42^\circ\\\\12x=138^\circ\\\\x=(138)/(12)\\\\x=11.5^\circ

So, m∠CBD = 4x+52=4(11.5)+52=98°

Hence, the value of ∠CBD is 98°.

M∠CBD=4x+52∘ m∠ABC=8x−10∘\qquad m \angle ABC = 8x - 10^\circm∠ABC=8x−10∘ Find m∠CBDm-example-1
User Henri Benoit
by
6.4k points
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