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2 votes
What is the focus of the parabola?

y=−14x2−2x−2

Enter your answer in the boxes.

User Ben Hardy
by
8.6k points

2 Answers

3 votes

Answer:

If this is for k12 I took the test and the right answer was (-4, 1)

Explanation:

User Kevin Potgieter
by
8.2k points
7 votes

Answer:

Explanation:

Given is a parabola


y=-14x^2-2x-2

Let us rewrite this in vertex form


y=-14(x+(1)/(14))^2-(27)/(14)

Hence vertex =
((-1)/(14) ,(-27)/(14) )

Axis of symmetry is


x=-(1)/(14)

a=
(1)/((14)4) =(1)/(56)

Hence focus would lie on the line of symmetry at a distance of a from vertex

So focus =
(-(1)/(14) ,-(27)/(14) -(1)/(56) )\\=(-(1)/(14) , -(109)/(56) )

User Jacob Swartwood
by
7.4k points

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