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The vertex of a quadratic function is located at (1, 4), and the y-intercept of the function is (0, 1). What is the value of a if the function is written in the form y = a(x – h)2 + k?

a =

User Bayram
by
6.8k points

2 Answers

5 votes

Answer:

-3

Explanation:

User UnicornsOnLSD
by
7.9k points
4 votes

Answer:


\large\boxed{y=-3(x-1)^2+4}

Explanation:

The vertex form of a quadratic function:


y=a(x-h)^2+k

where (h, k) is a vertex.

We have the vertex (1, 4). Therefore h = 1 and k = 4.

The y-intercept of the function is (0, 1). Put x = 0 and y = 1 to the equation


y=a(x-1)^2+4


1=a(0-1)^2+4


1=a(-1)^2+4


1=1a+4 subtract 4 from both sides


-3=a\to a=-3

User Michal Krasny
by
8.6k points

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