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A beam of light has 600 nm what is the frequency

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4 votes

Answer:


f = 5 * 10^(14) \; \text{Hz} if the wavelength is observed in vacuum.

Explanation:


f = (c)/(\lambda),

where


  • f is the frequency of this beam of light,

  • \lambda is its wavelength, and

  • c is the speed of light.


c \approx 3.00 * 10^(8) \; \text{m}\cdot \text{s}^(-1) in vacuum and in the earth atmosphere. However, the value of
c will be smaller in other media.


1 \; \text{nm} = 1 * 10^(-9) \; \text{m}.


  • \text{m} \cdot \text{s}^(-1) is the SI unit for speed.

  • \text{m} is the SI unit for distance.


\lambda = 600 \; \text{nm} = 600 * 10^(-9) \; \text{m} = 6.00 * 10^(-7) \;\text{m}.


f = (c)/(\lambda) = \frac{3.00 * 10^(8) \; \text{m}\cdot \text{s}^(-1)}{6.00 * 10^(-7)\; \text{m}} = 5 * 10^(14) \; \text{s}^(-1).

One [oscillation] in each second is the same as one Hertz
\text{Hz}. In other words,
1 \; \text{s}^(-1) = 1 \; \text{Hz}.


f = 5 * 10^(14) \; \text{s}^(-1) =5 * 10^(14) \; \text{Hz}.

User Dmitry Sobolev
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