Question

Help!!! Trigonometry

Answer 1

3.

`sin\ A = (opposite \angle A)/(hypotenuse)=(k)/(c)\\\\\\sin\ C = (opposite \angle C)/(hypotenuse)=(k)/(a)`

4.

`sin\ A=(k)/(c)\quad \rightarrow \quad c\ sin\ A=k\\\\\\sin\ C=(k)/(a)\quad \rightarrow \quad a\ sin\ C=k`

5.

`c\ sin\ A=a\ sin\ C\\\\(c\ sin\ A)/(ac)=(a\ sin\ C)/(ac)\\\\\\(sin\ A)/(a)=(sin\ C)/(c)\quad \rightarrow \quad \text{NOTE: This is the Law of Sines}`