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Let u=ln x and v= ln y. Write ln(square root x times y^2)
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Let u=ln x and v= ln y. Write ln(square root x times y^2)

User Jeiwan
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0.5u + 2v. This is because u can separate the logs to ln(sqrx) + ln(y^2) and use basic log principles to get 0.5lnx +2lny. Then u substitute
User Oj
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