87.8k views
3 votes
I really need help with this !

I really need help with this !-example-1

1 Answer

3 votes

It is obvious that Triangle BCD is congruent to Triangle EFG. EFG is twice the size of BCD.

Put the lengths into the pythagorean theorem equation. (the longest side is the hypotenuse)

So for Triangle BCD

3^2+b^2=5^2

(3×3)+b^2=(5×5)

9+b^2=25

So what plus 9 equals 25?

16

the square root of 16 is 4 so 4^2=16

9+16=25

Now since we know that Triangle EFG is twice the size of BCD remake the equation but the numbers will be:

6^2+8^2=10^2

Now check

(6×6)+(8×8)=(10×10)

36+64=100

100=100

So for Triangle EFG X=8

User MEURSAULT
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories