Question

PLEASE HELP AND EXPLAIN DUE TONIGHT

a 2kg bowling ball rolls at a speed of 10 m/s on the ground

circle one: KE, GPE or Both

show work finding the values of each rype of energy the object has..

Answer 1

100 J of kinetic energy but no gravitational potential energy if GPE of the ground is assumed to be zero.

Step-by-step explanation

Kinetic Energy

The ball carries kinetic energy for being in motion. The size of that energy is given as:

`\text{KE} = (1)/(2)\; m\cdot v^(2)`

where

• 
  `m` is the mass of the object, and
• 
  `v` is its speed.

SI units:

• 
  `\text{KE}`: joules.
• 
  `m`: kilograms.
• 
  `v`: meters per second.

For this ball:

`\text{KE} = (1)/(2)\; m\cdot v^(2) = (1)/(2) * 2* 10^(2) = 100 \; \text{J}`.

Gravitational Potential Energy

Whether the ball carries gravitational potential energy depends on the point of zero potential energy. The ball would carry GPE if the point of zero potential energy is chosen underground. However, the question emphasizes that the ball is "on the ground," which implies that the ground is the reference with a GPE of zero.

The gravitational field near the Earth's surface is constant. As a result, GPE is proportional to height relative to the ground (or the point of zero GPE). The ball is on the ground. Its height is zero. As a result, its GPE is also zero.