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3 votes
Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of arrow QP.

2 Answers

3 votes

Answer:

Component form of QP is
1\hat{i}+9\hat{j} and Magnitude of QP is √82

Explanation:

Given coordinates of the point P ( -7 , 16 ) and Point Q ( -8 , 7 )

Component form of QP =
(-7-(-8))\hat{i}+(16-7)\hat{j}

=
1\hat{i}+9\hat{j}

Magnitude of QP =
\left|QP\right|=√(1^2+9^2)

=
√(82)

Therefore, Component form of QP is
1\hat{i}+9\hat{j} and Magnitude of QP is √82

User Turner Bass
by
8.9k points
6 votes

Answer:

  • <1, 9>
  • √82

Explanation:

QP = P - Q

= <-7, 16> - <-8, 7> = <-7+8, 16-7>

QP = <1, 9>

___

|QP| = √(1^2 +9^2)

|QP| = √82

User Edwin Torres
by
8.7k points

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