Question

What is the solution set of the quadratic inequality 4(x+2)^2<=0?

Answer 1

x or A in edge

Explanation:

Answer 2

x=-2

Explanation:

4(x+2)^2<=0

Divide each side by 4

4/4(x+2)^2<=0/4

(x+2)^2<=0

The only this happens is if x+2 = 0

Squares are positive or zero , not negative so

x+2 =0

x+2-2 = 0-2

x=-2