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How to solve: sin(π×x-π/3)=-0.5​

How to solve: sin(π×x-π/3)=-0.5​-example-1
User Wisha
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2 Answers

2 votes

think about this

sin(?) = -1/2

? = pi * x - pi/3

User Alex Nikitin
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4.8k points
2 votes

Answer:

x = 3/2, 13/6.

Explanation:

In the range 0 to 2π the angles whose sine is -1/2 are 7π/6 and 11π/6 radians

So πx - π/3 = 7π/6

x - 1/3 = 7/6

x = 7/6 + 1/3 = 9/6 = 3/2.

and

πx - π/3 = 11π/6

x = 11/6 + 1/3 = 13/6.

User Noveaustack
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