Question

The pressure of a 1.0 liter balloon is at 1 atm at 293 K if you were to take the balloon into a freezer that is still at One ATM with a temperature of 263 K what would the new volume of the balloon be

Answer 1

Here we can say that number of moles as well as pressure will remain same for the balloon

so here we can say by ideal gas equation

`PV = nRT`

so here for constant pressure and constant number of moles we have

`(V_1)/(T_1) = (V_2)/(T_2)`

`(1)/(293) = (V)/(263)`

now by rearranging the equation we have

`V = (263)/(293)`

`V = 0.89 Liter`

so final volume will be 0.89 liter