Question

PLEASE HELP

Part A: Find the zeros if the function g(x)=(x^2-1)(x+3)
Part B: Graph the function g(x)
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Answer 1

1 and -3

Explanation:

Answer 2

The zeroes are x = -3 , -1 and 1.

Explanation:

(x^2 - 1)(x + 3) = 0

(x - 1)(x + 1) (x + 3) = 0

x- 1 = 0 gives x = 1

x + 1 = 0 gives x = -1

x + 3 = 0 gives x = -3.

The graph will rise from the left and will have 2 loops and pass through the x axis at x = -3 , x = -1 and x = 1.