Question

The temperature of chicken soup is 192.7°F. As it cools, the temperature of the soup decreases 2.3°F per minute. Part A What is the temperature in degrees Fahrenheit of the soup after 25 minutes? A. 27.3°F B. 57.5°F C. 135.2°F D. 250.2°F Part B How many minutes will it take for the soup to cool to 100.7°F? Enter the number in the box.

Answer 1

Part A: option C. 135.2°F

Part B: 40 min

Explanation:

Part A: What is the temperature in degrees Fahrenheit of the soup after 25 minutes?

1. Set an equation:

• Temperature = Initial temperature - decrease in temperature
• decrease in temperature = rate of decrease × time
• Variables:

temperature: T

initial temperature: To = 192.7°F

decrease rate: 2.3°F / min

time = t

• Equation: T = 192.7°F - 2.3(°F/min) × t

2. Substitute t = 25 min

• T = 192.7°F - 2.3 (°F/min) × 25 min = 135.2 °F

Part B. How many minutes will it take for the soup to cool to 100.7°F?

2. Solve the equation for t

• T = 192.7°F - 2.3(°F/min) × t ⇒ t = (192.7 °F - T) / (2.3 °F/min)

3. Substitute T = 100.7°F

• t = (192.7°F - 100.7°F) / (2.3 °F/min) = 40 min