Answer:
The first three terms of a different Fibonacci sequence are: a; b; a + b
Show that the 6th term of this sequence is 3a + 5b
4. (b) + (a + b) = a + 2b
5. (a + b) + (a + 2b) = 2a + 3b
6. (a + 2b) + (2a + 3b) = 3a + 5b
c) Given that the 3rd term is 7 and the 6th term is 29, find the value of a and the value of b.
a + b = 7
3a + 5b = 29
II - 3*I
2b = 8 --> b = 4
a + 4 = 7 --> a = 3