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The probability distribution table shows the proportion of people living in the five different regions of a city.

What is the probability that a person chosen at random, who lives in the city, lives in the East or West region?


Question 3 options:

0.06


0.12


0.18


0.3

The probability distribution table shows the proportion of people living in the five-example-1
User Candu
by
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2 Answers

1 vote

Answer:

P(east) + P(west) = 0.12 + 0.18 = 0.3

So 0.3 is the correct answer.

User Jimmiesrustled
by
7.8k points
3 votes

Answer: 0.3

Explanation:

From the given table, the probability that a person chosen at random, who lives in the city, lives in the East =
\text{P(East)= 0.12}

The probability that a person chosen at random, who lives in the city, lives in the West =
\text{P(West)= 0.18}

Since all the vents are independent .

Then, the probability that a person chosen at random, who lives in the city, lives in the East or West region is given by :-


\text{P(East or West)}=\text{P(East)+P(West)}\\\\=0.12+0.18=0.30

Hence, the probability that a person chosen at random, who lives in the city, lives in the East or West region =0.3

User Yariela
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