Question

Use the grouping method to factor the polynomial below completely. x3 + 2x2 + 3x + 6

Answer 1

Hello from MrBillDoesMath!

Answer:

(x+2) ( x^2 + 3)

Discussion:

x^3 + 2x^2 + 3x + 6 =

( x^3 + 2x^2) + (3x + 6) = => factor "x^2" from the first term; factor 3

from the second term

x^2( x + 2) + 3( x+2) = => factor (x+2) from each term

(x+2) ( x^2 + 3)

Thank you,

MrB

Answer 2

(x+2)(x²+3)

Explanation:

We have given an expression.

x³+2x²+3x+6

We have to factor by using grouping method.

Making two groups of two terms that has any common factor, we have

(x³+2x²)+(3x+6)

Since x² is common factor in first parentheses and 3 is common in second parentheses.

taking common, we have

x²(x+2)+3(x+2)

Taking x+2 as common, we have

(x+2)(x²+3)

Hence, x³+2x²+3x+6 has two factors (x+2) and (x²+3).