Step-by-step explanation:
The tangential speed of Andrea is given by :
![v=r\omega](https://img.qammunity.org/2022/formulas/physics/college/p80w7cb55zc6saxpags5d25k0jy0f70dep.png)
Where
r is radius of the circular path
ω is angular speed
The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'
r' = 2r
New angular speed,
![v'=r'\omega'\\\\v'=(2r)\omega\\\\v'=2r\omega\\\\v'=2v](https://img.qammunity.org/2022/formulas/physics/college/eiyuiz3vesltboosxb4tse8zid8mm6uc7u.png)
New angular speed is twice that of the Chuck's speed.