Question

Three kids pull on a toy. kim pulls with a force of 30 n north, jim pulls with a force of 30 n south, and tim pulls with a force of 15 n east. the acceleration of the toy is

Answer 1

As we can see the figure we will have

`F_1 = 30 N` North

`F_2 = 30 N` South

`F_3 = 15 N` East

now for net force on Toy we need to add all forces along with the direction (Vector Sum)

`F = F_1 + F_2 + F_3`

`F = 30\hat j + 15 \hat i + 30 (-\hat j)`

now from above we have

`F = 15 N` towards East

so net force on the toy is 15 N towards East

now the acceleration of toy is given as

`a = (F)/(m)`

`a = (15)/(m)`

here m = mass of toy