Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO
![tan 65 = (h)/(45-x) = 2.14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lwi1tbctxrj50ep5iy29vvx1h5uve9q1iv.png)
![h=2.14(45-x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aknp1azpl6lp1bif1vtq3bn66v4xiy5xmh.png)
From ΔBCO
![tan80 = (h)/(x) = 5.67](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ka5x8tsty8ftfnd7ar1wn0nqticygbn50u.png)
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore
![cos80 = (x)/(OB)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m6vp47hyf96g5ra71eddviq9mityuthmk0.png)
![0.174 = (12.33)/(OB)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z47swzwfxcj9vp06ll2smb0dter258t9kx.png)
![OB = (12.33)/(.174)=70.86=71ft.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/crh77ibf3a8ewau44ntukkft953m0t09np.png)
Therefore 71 ft is the distance between B and the top of the hill.