Answer:
H: P=4, increase=2, f(x) = 4·2^x
I: P=51, increase=2, f(x) = 51·2^x
J: P=4, increase=4, f(x) = 4·4^x . . . . Javier's exponential function
K: P=11, increase=3, f(x) = 11·3^x
Explanation:
The initial value is P. The "increase" is the number being shared with at each stage of growth. This is also known as the "growth factor."
The exponential function follows the model given in the problem statement:
f(x) = P·increase^x
When P=51 and increase=2, this is ...
f(x) = 51·2^x