Question

A basket ball player makes 80% of his free throws.if he attempts two free throws, what are the chance that he miss both free throws

(options)
.4%
.6%
.8%
.12%
.20%

Answer 1

4%

Explanation:

1) The player will miss 20% of their free throws.

2) That can be modeled by the fraction: 1/5.

3) Multiply 1/5 by 1/5 (he has a 1/5 chance of missing his shot for each shot so you multiply them together to get the probability of the player missing both).

4) 1/5 x 1/5 = 1/25

5) 1/25 can be modeled by the percent: 4%.