Answer:
1. x = 4
2. x = 20
Explanation:
1.
ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:
![(AC)/(AJ)=(AB)/(AK)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lzydhp5rw1xh4s4krsh95t5p429kf9bj66.png)
We have:
AC = 1 + 4 = 5
AJ = 1
AB = 1 + x
AK = 1
Substitute:
![(5)/(1)=(1+x)/(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kgnhnp03vp38x4vbm7matuefxcrkvyhoq9.png)
subtract 1 from both sides
![4=x\to x=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u37zsga4tiyl1no1ezblqx0gkqppwz3fvw.png)
2.
ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:
![(VU)/(VM)=(VT)/(VN)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n3kt9u40xyurwa71p2xvrhyzyn0c4u30qy.png)
We hve:
VU = x + 8
VM = x
VT = 49
VN = 49 - 14 = 35
Substitute:
cross multiply
use the distributive property a(c + b) = ab + ac
subtract 35x from both sides
divide both sides by 14
![20=x\to x=20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/falh0kqq4uit6hra03jllhuwi6hs4djc79.png)