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Choices
16-64pi
256-8pi
64-16pi
256-64pi

Choices 16-64pi 256-8pi 64-16pi 256-64pi-example-1
User Wayne Kao
by
6.2k points

1 Answer

0 votes

Answer:

Option 4 is correct.i.e, ( 256 -
64\pi ) sq. inch

Explanation:

Given : A Square is circumscribed about a circle.

Radius of Circle = 8 inch.

To find : Area of region inside the square but outside of circle.

From Given figure, we have side of square = Diameter of circle

= 2 × 8 = 16 inch.

Area of Required region = Area of Square - Area of circle

= side × side -
\pi r^2

= 16 × 16 -
\pi* 8^2

= ( 256 -
64\pi ) sq. inch

Therefore, Option 4 is correct.

User Corvo
by
6.2k points