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3/4, 1, 5/4 find the 22nd & 43rd terms

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Answer:

6 and 45/4

Explanation:

If the first three terms of your sequence are 3/4, 1, 5/4, the first term is obviously 3/4 and the common difference is 1/4. This is an arithmetic sequence.

We can write a general formula for the nth term of this sequence as follows:

a(n) = a(1) + (n-1)(1/4), or, since a(1) = 3/4,

a(n) = 3/4 + (n-1) / 4

Then a(22) = 3/4 + (22-1)/4, or 3/4 + 21/4, or 24/4, or just 6.

a(43) = 3/4 + (43-1)/4, or 3/4 + 42/4, or 45/4.

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