Answer:
x = 14 is an extraneous solution
Explanation:

Divide both sides by 4.

Square both sides.



Since we squared both sides, we much check for extraneous solutions because the process of squaring both sides can introduce extraneous solutions.
Check x = 14:





16 = -16 is a false statement, so the solution we found, x = 14, is an extraneous solution.