Answer:
![x^(2) +2x+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a147tijhxu9ijs4p61rq63rmkk0bh611eh.png)
Explanation:
Wehn you are faced with the next division you have to factorize the polynomial function:
![(x^(3)+3x^(2)+5x+3)/(x+1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5d7nu3scogm11a2w6vtbqvdumqwapovjpb.png)
Now you have to separate it in two factors, one of them being (x+1) so you can after eliminate it:
![((x+1)(x^(2)+2x+3))/(x+1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mhdoxyr5k9m6oghk4zm75up2bf2yaclppx.png)
And now you just eliminate the same binomials from both sides of the division and you´d end up with the next division:
![(x^(2)+2x+3)/(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pgvs1tjrfwymdh9o5ih8m7fad1e6tovp8n.png)
And the answer to the division is:
![x^(2) +2x+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a147tijhxu9ijs4p61rq63rmkk0bh611eh.png)