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What is the simplest form of the radical expression the square root of 2 + the square root of 5 divided by the square root of 2 - the square root of 5

User Erik Allen
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2 Answers

4 votes

Answer:

1/-3 (7+2√10) is the simplification of given expression.

Explanation:

We have given the expression:

√2+√5 /√2-√5

We have to find the simplest form of the given expression.

For simplification of this expression we have to multiply and divide the expression by (√2+√5).

(√2+√5)/(√2-√5) ×(√2 +√5)/(√2+√5)

(√2+√5)²/(√2)² - (√5)²

(√2+√5)²/ (2-5)

(√2)²+(√5)²+ 2(√2)(√5) / -3

2+5+2√10 /-3

(7+2√10) / -3

1/-3 (7+2√10) is the simplification of given expression.

User MajorTom
by
8.4k points
4 votes

For this case, we have the following expression:


\frac {\sqrt {2} + \sqrt {5}} {\sqrt {2} - \sqrt {5}}

We must rationalize, that is, we multiply the numerator and denominator by
\sqrt {2} + \sqrt {5}:


\frac {(\sqrt {2} + \sqrt {5}) * (\sqrt {2} + \sqrt {5})} {(\sqrt {2} - \sqrt {5}) * (\sqrt { 2} + \sqrt {5})} =\\\frac {(\sqrt {2} + \sqrt {5}) ^ 2} {(\sqrt {2} - \sqrt {5}) (\sqrt {2} + \sqrt {5})} =\\\frac {(\sqrt {2} + \sqrt {5}) ^ 2} {(\sqrt {2}) ^ 2+ √(2) \sqrt {5} - \sqrt {5} \sqrt {2} - (\sqrt {5}) ^ 2} =


\frac {(\sqrt {2} + \sqrt {5}) ^ 2} {2-5} =\\\frac {(\sqrt {2} + \sqrt {5}) ^ 2} {- 3} =\\\frac {(\sqrt {2}) ^ 2 + 2 \sqrt {2} \sqrt {5} + (\sqrt {5}) ^ 2} {- 3} =\\\frac {2 + 2 \sqrt {10} +5} {- 3} =


- \frac {1} {3} (7 + 2 \sqrt {10})

ANswer:


- \frac {1} {3} (7 + 2 \sqrt {10})

User Yungchin
by
8.3k points

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