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The coach of softball team is holding tryouts and can take only 2 more players for the team. There are 8 players trying out . How different groups of 2 players could possibly be chosen?

User Gileri
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2 Answers

3 votes

Answer:

28 groups of 2.

Explanation:

That would be the number of possible combinations of 2 out of 8 , written as 8C2.

8C2 = 8! / (8-2)! 2!

A quick way of working this out is 8*7 / 2*1 . The above formula simplifies to this. Note the numerator starts with 8 then you multiply by 7 (8-1). The number of values in the numerator depends on the combination value ( in this case it is 2). The denominator here is 2*1.

So the answer is 8*7 / 2*1 = 28 ways.

Other examples of combinations:

7C4 = 7*5*4*3 / 4*3*2*1

10C3 = 10*9*8 / 3*2*1.

I hope this helps.

User Basim Khajwal
by
4.6k points
2 votes

Answer:

64

Explanation:

User Verna
by
5.1k points