Question

A concert loudspeaker suspended high off the ground emits 39 w of sound power. a small microphone with a 1.0 cm2 area is 60 m from the speaker. part a what is the sound intensity at the position of the microphone?

Answer 1

As we know that intensity of sound is defined as power received per unit area

so here the power of source is given as

`P = 39 W`

distance of microphone is given as

`d = 60 m`

now if loudspeaker is considered as spherical source then we will have

`Intensity = (power)/(area)`

here

r = d = 60 m

`Intensity = (39)/(4\pi (60^2))`

`Intensity = 0.86 * 10^(-3) W/m^2`