Question

Two students are standing next to one another. One student has a mass of 79.0 kg, and the other has a mass of 93.5 kg. If they are standing so that their centers of mass are a distance of 1.12 m apart, what is the force of the gravitational attraction between them?

A. 4.40 * 10^-7 N
B. 3.93 * 10^-7 N
C. 1.29 * 10^-6 N
D. 8.77 * 10^-6 N

Answer 1

`F=3.93* 10^(-7)\ N`

Step-by-step explanation:

Mass of student 1, m₁ = 79 kg

Mass of student 2, m₂ = 93.5 kg

The students are 1.12 m apart, d = 1.12 m

We need to find the force of the gravitational attraction between them. The force of gravitational force is given by :

`F=G(m_1m_2)/(r^2)\\\\F=6.67* 10^(-11)* (79* 93.5)/((1.12)^2)\\\\=3.93* 10^(-7)\ N`

So, the force of gravitational attraction between them is
`3.93* 10^(-7)\ N`. Hence, the correct option is (B).