Question

If c and k are the roots of 6-x-x^2=0 find c + k. pls solve like a quadratic equation​

Answer 1

by Viete's formula

c + k = - koef x/koef x²

= - (-1)/(-1) = -1

Answer 2

c + k = - 1

Explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

Then the sum of the roots = -
`(b)/(a)` and

The product of the roots =
`(c)/(a)`

- x² - x + 6 = 0 is in standard form

with a = - 1, b = - 1 and c = 6

The roots are c and k, hence

c + k = -
`(-1)/(-1)` = - 1