Question

1.Which characteristic is common to all permanent magnets?

2. A proton enters a uniform magnetic field at a speed v . The magnetic field is oriented at an angle to the direction of the proton, and the strength of the field is B . Which change or set of changes would double the magnitude of the force on the proton?


answer all three please.

30 pts !!!!!!!

Answer 1

1.

Answer:

Two poles identified as North and South poles

Step-by-step explanation:

All magnets must have different and opposite poles on either sides in which one pole must be south pole while other is North pole.

2.

Answer:

Doubling B

Step-by-step explanation:

Force on the moving charge is given by

`F = qvBsin\theta`

so here we know that force is proportional to the product of q, v and B

so on doubling any one of the variable will increase the force to double.

3.

Answer:

`v = 8.8 * 10^3 m/s`

Step-by-step explanation:

As electron passes undeviating so we can say that

`F_e = F_b`

`qE = qvB`

`v = (E)/(B)`

`v = (4.6 * 10^4)/(5.2)`

`v = 8846.15 m/s`

Answer 2

1)

Two poles identified as North and South.

All magnets have North and South ends with magnetic field lines that leave the North end and loop around to the South end.

2)

F =QBVsinΔ

As we can see from the formula, force is directly proportional to B so doubling the B will double the force.

3)

v = E/B

Since field are perpendicular so sin90 = 1

v = 4.6/10^4 / 5.2)

v = 8846.15 m /s