Answer:
Assuming the two sides are not the hypotenuse, then the third side would equal 5
Explanation:
using the formula
![a^(2) + b^(2) = c^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wq3kmoil0so9sluxvkwaim8ro5cf5ry9b4.png)
c is the hypotenuse while a and b are the sides.
![3^(2) + 4^(2) = c^(2) \\](https://img.qammunity.org/2020/formulas/mathematics/high-school/jvh2xytx7mvt9uhrvwp9pxrjeqv1i4bfjq.png)
so that simplifies to 9 + 16 =
![c^(2)](https://img.qammunity.org/2020/formulas/mathematics/college/ih9sjj7vv27eb750d3jpbvq12m5qrk2q9d.png)
25=
![c^(2) \\](https://img.qammunity.org/2020/formulas/mathematics/high-school/oqi2x7nlocre1o5uqrntfsagaw6ndn4xq8.png)
in order to get just c alone, we must square both sides
![√(25) = √(c)^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/yw18y9iia05gu0gipbzsea101y438xs9ab.png)
this cancels out on the right side and leaves you with 5 on the left
therefore c=5