Question

The equation of a circle is (x + 6)2 + (y - 1)2 = 12. Determine the coordinates of the center of the circle.

Center (-1, 6)

Center (1, -6)

Center (-6, 1)

Center (6, -1)

Answer 1

The correct answer is third (-6, 1)

Explanation:

Given:

(x + 6)² + (y - 1)² = 12

The equation of a circle in the canonical form from which you can directly determine coordinates of the center is:

(x - p)² + (y - q)² = r² where p(x -axis) and q (y-axis) are coordinates of a circle.

p = - 6 and q = 1 => ( -6, 1)

God with you!!!

Answer 2

Center is (-6,1).

Explanation:

Since, we know that

Equation of circle in center-radius form is:

(x-h)²+(y-k) = r²

Where r is radius of circle and (h,k) is center of circle.

Given equation of circle is:

(x+6)²+(y-1)² = 12

We have to find the center of given circle.

(x-(-6))²+(y-(1))² = 12

Comparing given equation with above equation , we have

h = -6 and k = 1

hence , center of circle is (-6,1).