Answer:
the kinetic energy of body B is twice the kinetic energy of body A
Step-by-step explanation:
The kinetic energy of a body is given by
K = ½ m v²
If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.
Therefore if the mass of body b is twice the mass of body A

= ½ (2
) v²
K_{b} = 2 (½ m_{a} v²)
K_{b} = 2 K_{a}
therefore the kinetic energy of body B is twice the kinetic energy of body A