Question

A bird flies from its nest and lands in a tree that is 2400m due west. If the bird can fly at an average velocity of 9.0m/s, for how long, in seconds, is the bird in flight?

Answer 1

Answer: 266.67 s

Explanation:

Average velocity is the rate of change of displacement.

Bird flies 2400 m due west at an average velocity of 9.0 m/s.

`\text{Average velocity}=(Displacement)/(time)`

Given, average velocity, v = 9.0 m/s

Displacement, d = 2400 m

`v=(d)/(t)\Rightarrow t=(d)/(v)\\ t=(2400 m)/(9.0,m/s)=266.67s`

Thus, bird was in flight for 266.67 s to fly from nest to land in a tree 2400 m due west.