Answer:
Choice a is correct answer.
Explanation:
We have given four set of points.
(a) (-14,12) and (5,12)
(b) (-5,19) and (-12,19)
(c) (-20,5) and (1,5)
(d) (14,12) and (5,12)
We have to find the distance between each set of points.
The formula for distance is:
d = √(x₂-x₁)²+(y₂-y₁)²
The set of points which have 19 units distance is our answer.
For (a):
d =√(5-(-14)²+(12-12)²
d = √(5+14)²+(0)²
d = 19 units
for (b) :
d = √(-12-(-5))²+(19-19)²
d = √(-12+5)²+(0)²
d = √(-7)²
d = 7 units
for (c):
d = √(1-(-20)²+(5-5)²
d = √(1+20)²+(0)²
d = 21 units
for (d):
d =√(5-14)²+(12-12)²
d = √(-9)²+(0)²
d = 9 units
Hence , correct choice is (a).