Question

A car starts from rest and accelerates uniformly to reach a speed of 21m/s in 7.0 What was the acceleration of the object?​

Answer 1

3 m/s/s

Working

A=V-U/t
A=21-0/7
A=21/7
A=3 m/s/s

The units it’s is usually written as ms2 where the 2 means squared

Answer 2

Acceleration of the object,
`a=3\ m/s^2`

Step-by-step explanation:

It is given that,

Initial speed of the object, u = 0

Final speed of the object, v = 21 m/s

Time taken, t = 7 s

Let a is the acceleration of the object. Using the equation of kinematics as :

v = u + a × t

v = a × t

`a=(v)/(t)`

`a=(21\ m/s)/(7\ s)`

`a=3\ m/s^2`

So, the acceleration of the object is
`3\ m/s^2`. Hence, this is the required solution.