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Find the x-and y-intercept of the graph of each equation 4x-3y=12

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For y-intercept, x=0, as any y-intercept would be located at a x-coordinate of 0.

Put 0 into x:

4(0) - 3y =12

-3y = 12

y = 12/ -3

y = - 4

Therefore the y-intercept is -4.

Similar as the above,for x-intercept, y=0, as any x-intercept would be located at a y-coordinate of 0.

Put 0 into y:

4x - 3(0) = 12

4x = 12

x = 12/4

x = 3

Therefore, the x-intercept is 3.

Hope it helps!

User Goosemanjack
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