Question

Evaluate 32y−3+53z\dfrac32y-3+\dfrac53z ​2 ​ ​3 ​​y−3+ ​3 ​ ​5 ​​z start fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6 y=6 y, equals, 6 and z=3z=3 z=3 z, equals, 3 .

Answer 1

11

Explanation:

Follow me

Peace out!

Answer 2

11.

Explanation:

We are asked to evaluate the expression
`(3)/(2)y-3+(5)/(3)z`, when y=6 and z=3.

To evaluate our expression at given values we will just substitute y=6 and z=3 in our given expression.

`(3)/(2)*6-3+(5)/(3)*3`

According order of operations (PEMDAS) we will multiply or divide our expression from left to right.

`3*3-3+5*1`

`9-3+5`

`6+5`

`11`

Therefore, the value of our given expression at y=6 and z=3 is 11.