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Find the indicated values, where g(t)=t²-t and f(x)=1+x.

f(2g(1))
A 1
B 3
C 30
D -1

User KitKat
by
6.3k points

2 Answers

3 votes

Answer:

A

Explanation:

given g(t) = t² - t and f(x) = 1 + x

To evaluate f(2g(1), evaluate g(1), multiply by 2 and use this value to evaluate f(x)

g(1) = 1² - 1 = 1 - 1 = 0 ⇒ 2g(1) = 2 × 0 = 0

f(0) = 1 + 0 = 1 → A

User Abu Shumon
by
5.8k points
1 vote

Answer:

Explanation:

f(2g(1)) = f(2×0) because : g(1) = 1² - 1 = 0

f(2g(1)) = f(0) = 1+0 = 1 ......answer : A)1

User Stephen Cox
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5.8k points